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DENSE_RANK
Applies to ✅ Open Source Edition ✅ Express Edition ✅ Professional Edition ✅ Enterprise Edition
The DENSE_RANK()
hypothetical set function calculates the rank without gaps of the hypothetical value, i.e. dense ranks will be 1, 1, 1, 2, 3, 3, 4 (RANK produces values with gaps, e.g. 1, 1, 1, 4, 5, 5, 7)
SELECT dense_rank(0) WITHIN GROUP (ORDER BY AUTHOR_ID), dense_rank(1) WITHIN GROUP (ORDER BY AUTHOR_ID), dense_rank(2) WITHIN GROUP (ORDER BY AUTHOR_ID) FROM BOOK
create.select( denseRank(val(0)).withinGroupOrderBy(BOOK.AUTHOR_ID), denseRank(val(2)).withinGroupOrderBy(BOOK.AUTHOR_ID), denseRank(val(4)).withinGroupOrderBy(BOOK.AUTHOR_ID)) .from(BOOK)
Producing:
+---------------+---------------+---------------+ | dense_rank(0) | dense_rank(1) | dense_rank(2) | +---------------+---------------+---------------+ | 1 | 1 | 2 | +---------------+---------------+---------------+
Dialect support
This example using jOOQ:
denseRank(val(0)).withinGroupOrderBy(BOOK.ID)
Translates to the following dialect specific expressions:
-- AURORA_POSTGRES, H2, ORACLE, POSTGRES, YUGABYTEDB dense_rank(0) WITHIN GROUP (ORDER BY BOOK.ID) -- ACCESS, ASE, AURORA_MYSQL, BIGQUERY, COCKROACHDB, DB2, DERBY, DUCKDB, EXASOL, FIREBIRD, HANA, HSQLDB, INFORMIX, -- MARIADB, MEMSQL, MYSQL, REDSHIFT, SNOWFLAKE, SQLDATAWAREHOUSE, SQLITE, SQLSERVER, SYBASE, TERADATA, TRINO, VERTICA /* UNSUPPORTED */
(These are currently generated with jOOQ 3.19, see #10141), or translate your own on our website
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